Some Sql Server Interview Questions
* Difference between Set and Select
Ans:
1) Set is a ANSI standard for variable assignment.
Select is a Non-ANSI standard when assigning variables.We can assign only one variable at a time
2) We can assign multiple variable at a time.When assigning from a query that returns more than one value, SET will fail with an error.
When assigning from a query that returns more than one value, SELECT will assign the last value returned by the query and hide the fact that the query returned
* What is Network Packet Size in SQL
Ans:
NPS(Network Packet Size) is the size of the TDS (tabular data stream) packets used to communicate between your applications and your relational database engine and default packet size is 4 kilobytes and its manily depends on network packet size configuration option.
* How many different locks in SQL SERVER
Ans:
(1)Intent
(2)shared
(3)Update
(4)Exclusive
(5)Schema
(6)Bulk Update
* Diffrence between temp table and table variable
Ans:
(1)Temp Tables are created in the SQL Server TEMPDB database and therefore require more IO resources and locking. Table Variables and Derived Tables are created in memory.
(2)Temp Tables will generally perform better for large amounts of data that can be worked on using parallelism whereas Table Variables are best used for small amounts of data (I use a rule of thumb of 100 or less rows) where parallelism would not provide a significant performance improvement.
(3)You cannot use a stored procedure to insert data into a Table Variable or Derived Table. For example, the following will work: INSERT INTO #MyTempTable EXEC dbo.GetPolicies_sp whereas the following will generate an error: INSERT INTO @MyTableVariable EXEC dbo.GetPolicies_sp.
(4)Derived Tables can only be created from a SELECT statement but can be used within an Insert, Update, or Delete statement.
(5) In order of scope endurance, Temp Tables extend the furthest in scope, followed by Table Variables, and finally Derived Tables.
* What is Cursor
Ans:
Cursor is a database object used by applications to manipulate data in a set on a row-by-row basis, instead of the typical SQL commands that operate on all the rows in the set at one time. For example, you can use cursor to include a list of all user databases and make multiple operations against each database by passing each database name as a variable
* Write some disadvantage of Cursor
Ans:
Cursor plays there row quite nicely but although there are some disadvantage of Cursor . Because we know cursor doing roundtrip it will make network line busy and also make time consuming methods. First of all select query gernate output and after that cursor goes one by one so roundtrip happen.Another disadvange of cursor are ther are too costly because they require lot of resources and temporary storage so network is quite busy.
* Can you tell me the difference between DELETE and TRUNCATE commands
Ans:
Delete command removes the rows from a table based on the condition that we provide with a WHERE clause. Truncate will actually remove all the rows from a table and there will be no data in the table after we run the truncate command.
How to pad a numeric type column with leading zeros?
Execute the following Microsoft SQL Server T-SQL example scripts to demonstrate SQL padding of numbers and strings with leading and trailing zeros as well as with other designated characters, and techniques for removing (trim) leading zeros.
– SQL Server leading zero – T-SQL padding numbers – lpad tsql – sql pad zero
SELECT ListPrice,
Padded=RIGHT(’0000000000′ + CONVERT(VARCHAR,ListPrice), 10)
FROM AdventureWorks2008.Production.Product WHERE ListPrice > 0.0
————
– T SQL pad leading zeros – transact sql leading zeros
SELECT ProductID, ReorderPoint = REPLACE(STR(ReorderPoint, 6), SPACE(1), ’0′)
FROM AdventureWorks2008.Production.Product
/* ProductID ReorderPoint
1 000750
2 000750
3 000600 */
————
– SQL Server leading zero – SQL leading zeros – sql server pad leading zero
USE AdventureWorks2008;
DECLARE @Number int = 789
SELECT RIGHT (’000000′+ CAST (@Number AS varchar), 6)
– 000789
————
USE AdventureWorks;
– SQL padding salary pay rate money data type with leading zeroes
– SQL left pad number – prefix number with zeros – sql server leading zero
– SQL convert number to text – cast number to varchar string
SELECT EmployeeID,
Rate,
PaddedRate = RIGHT(REPLICATE(’0′,8) + CAST(Rate AS VARCHAR(8)),8)
FROM HumanResources.EmployeePayHistory
/* Partial results
EmployeeID Rate PaddedRate
1 12.45 00012.45
2 13.4615 00013.46
3 43.2692 00043.27
*/
– SQL zero padding ListPrice money data type – t sql leading zero
– SQL left pad – T-SQL string concatenation – sql concat
– SQL convert number to string – pad numeric with zeros
SELECT ProductID,
ListPrice,
PaddedListPrice = RIGHT(REPLICATE(’0′, 8) + CAST(ListPrice AS VARCHAR(8)),8)
FROM Production.Product
/* Results sample
ProductID ListPrice PaddedListPrice
965 742.35 00742.35
*/
– SQL month leading zero – sql pad month number with zero
SELECT RIGHT(’0′ + convert(varchar(2), month(GetDate())), 2)
– 06
———-
– trim leading zeros – sql trim leading zeros – remove leading zeros sql
USE AdventureWorks2008;
DECLARE @num varchar(32)= ’00091234560′
SELECT right(@num, len(@num)+1 – patindex(‘%[^0]%’, @num))
– 91234560
————
– SQL pad numeric data type – SQL pad digits – transact sql leading zeros
– SQL pad with leading zeroes – append leading zeros – T-SQL top function
– SQL pad with trailing zeroes – MSSQL append trailing zeros
– SQL cast money to numeric – cast numeric to string – mssql newid function
SELECT TOP (5)
ProductName = Name,
ListPrice = RIGHT(REPLICATE(’0′, 10)
+ CAST(CAST(ListPrice AS NUMERIC(9,3)) AS VARCHAR) ,10)
FROM AdventureWorks.Production.Product
ORDER BY NEWID()
/* ProductName ListPrice
LL Mountain Frame – Black, 40 000249.790
HL Touring Frame – Yellow, 46 001003.910
Bike Wash – Dissolver 000007.950
Metal Sheet 7 000000.000
HL Road Frame – Red, 56 001431.500
*/
———-
– PAD leading zeros function – sql server leading zeros – UDF
USE AdventureWorks2008;
GO
CREATE FUNCTION fnPadNumber
(@n DECIMAL(26,2),
@length TINYINT)
RETURNS VARCHAR(32)
AS
BEGIN
RETURN ( replicate(’0′,@length – len(convert(VARCHAR(32),@n))) +
convert(VARCHAR(32),@n))
END
GO
SELECT dbo.fnPadNumber(1234567890.12,16)
– 0001234567890.12
————
– T SQL computed column zero padding – sql generate alphanumeric sequence
USE tempdb; — SQL Server 2008 T-SQL
CREATE TABLE Celebrity (
ID INT IDENTITY ( 1 , 1 ) PRIMARY KEY,
CelebrityID AS ‘CEL’ + RIGHT(’0000′ + CAST( ID as varchar),5), — computed column
FirstName VARCHAR(32),
LastName VARCHAR(32),
ModifiedDate DATE DEFAULT getdate())
GO
INSERT Celebrity
(FirstName,
LastName)
VALUES(‘Jennifer’,'Aniston’),
(‘Drew’,'Barrymore’),
(‘Diana’,'Princess of Wales’),
(‘Tom’,'Jones’),
(‘Lucille’,'Ball’),
(‘Frank’,'Sinatra’),
(‘Elvis’,'Presley’)
SELECT * FROM Celebrity
GO
– CelebrityID is zero padded alphanumeric sequence
/*
ID CelebrityID FirstName LastName ModifiedDate
1 CEL00001 Jennifer Aniston 2012-07-04
2 CEL00002 Drew Barrymore 2012-07-04
3 CEL00003 Diana Princess of Wales 2012-07-04
4 CEL00004 Tom Jones 2012-07-04
5 CEL00005 Lucille Ball 2012-07-04
6 CEL00006 Frank Sinatra 2012-07-04
7 CEL00007 Elvis Presley 2012-07-04
*/
– Cleanup demo
DROP TABLE Celebrity
GO
————
– SQL removing leading zeros when no spaces in string – trimming Leading Zeros
USE AdventureWorks2008;
DECLARE @NumberString varchar(16)=’000000246′
SELECT REPLACE(LTRIM(REPLACE(@NumberString, ’0′, ‘ ‘)), ‘ ‘, ’0′)
– 246
————
– SQL remove leading zeros – sql trim leading zeros – numeric test
DECLARE @StringWithLeadingZeros VARCHAR(12) = ’000000654321′
SELECT CAST(CAST(@StringWithLeadingZeros AS INT) AS VARCHAR(10))
WHERE ISNUMERIC (@StringWithLeadingZeros)=1
– 654321
————
– LPAD & RPAD string scalar-valued user-defined functions (UDF)
USE AdventureWorks;
GO
– Left pad string function
CREATE FUNCTION LPAD
(@SourceString VARCHAR(MAX),
@FinalLength INT,
@PadChar CHAR(1))
RETURNS VARCHAR(MAX)
AS
BEGIN
RETURN
(SELECT Replicate(@PadChar,@FinalLength – Len(@SourceString)) + @SourceString)
END
GO
– T-SQL Test left padding
SELECT LeftPaddedString = dbo.LPAD(Cast(84856 AS VARCHAR),12,’0′)
GO
– 000000084856
– MSSQL right pad string function
CREATE FUNCTION RPAD
(@SourceString VARCHAR(MAX),
@FinalLength INT,
@PadChar CHAR(1))
RETURNS VARCHAR(MAX)
AS
BEGIN
RETURN
(SELECT @SourceString + Replicate(@PadChar,@FinalLength – Len(@SourceString)))
END
GO
– Test right padding
SELECT RightPaddedString = dbo.RPAD(Cast(84856 AS VARCHAR),12,’*')
GO
– 84856*******
———-
– Padding a money column with leading zeroes – sql convert leading zero
– SQL convert money data type to string
SELECT PaddedUnitPrice = RIGHT(replicate(’0′,20) +
convert(varchar,UnitPrice,1), 20)
FROM Northwind.dbo.Products
/* Partial results
PaddedUnitPrice
00000000000000018.00
00000000000000019.00
00000000000000010.00
00000000000000022.00
*/
/**************** Zero padding other numeric data ****************/
– SQL Server 2008 version featuring the LEFT function
– SQL convert integer to text – convert integer to varchar
USE AdventureWorks2008;
DECLARE @InputNumber int = 522, @OutputLength tinyint = 12
DECLARE @PaddedString char(12)
SET @PaddedString = LEFT( replicate( ’0′, @OutputLength ),
@OutputLength – len( @InputNumber ) ) + convert( varchar(12), @InputNumber)
SELECT PaddedNumber=@PaddedString
/* Result
PaddedNumber
000000000522
*/
– SQL format currency and pad with leading spaces
– SQL Server lpad to 9 characters
SELECT TOP (3) ProductName=Name,
Price= CONVERT(char(9), ListPrice, 1)
FROM Production.Product
WHERE ListPrice > 0.0 ORDER BY Newid()
/*
ProductName Price
LL Touring Frame – Blue, 62 333.42
LL Road Seat Assembly 133.34
Road-250 Red, 58 2,443.35
*/
————
– Padding with zeroes in the middle of string
DECLARE @Number varchar(10)
SET @Number = ’99999′
PRINT ‘TRK’ + REPLICATE(’0′, 12 – LEN(@Number)) + @Number
SELECT [Zero Padding]=’TRK’ + REPLICATE(’0′, 12 – LEN(@Number)) + @Number
– Result: TRK000000099999
– Applying the STUFF string function for zero padding
– SQL convert integer data type to string
DECLARE @SerialNo int, @OutputSize tinyint
SET @OutputSize = 10
SET @SerialNo = 6543
SELECT PaddedSerialNo = STUFF(replicate(’0′, @OutputSize),
@OutputSize – len(@SerialNo)+1, len(@SerialNo), convert(varchar(9),@SerialNo))
– Result: 0000006543
– SQL pad integer with 0-s
– SQL str function – numeric to character conversion
SELECT TOP 5
CAST(replace(str(ProductID,6),’ ‘,’0′) AS char(6)) AS ProdID
FROM AdventureWorks.Production.Product
ORDER BY Name
/* Results
ProdID
000001
000879
000712
000003
000002
*/
– SQL pad string with character
– SQL create function
– SQL user-defined function
CREATE FUNCTION dbo.fnLeftPadString (
@Input VARCHAR(255),
@PadChar CHAR(1),
@LengthToPad TINYINT
)
RETURNS VARCHAR(255) AS
BEGIN
DECLARE @InputLen TINYINT
SET @InputLen = LEN(@Input)
RETURN
CASE
WHEN @InputLen < @LengthToPad
THEN REPLICATE(@PadChar, @LengthToPad – @InputLen) + @Input
ELSE @Input
END — CASE
END — UDF
GO
– SQL pad string – left padding – SQL left pad with asterisk
– SQL check printing – SQL currency formatting
DECLARE @DollarAmount varchar(20)
SET @DollarAmount = ’234.40′
SELECT PaddedString=’$'+dbo.fnLeftPadString(@DollarAmount, ‘*’, 10)
GO
– Result: $****234.40
– SQL currency formatting with asterisk-fill
DECLARE @Amount MONEY
SET @Amount = ’3534.40′
SELECT CurrencyFormat = ‘$’ + REPLACE(Convert(char(12),@Amount,1),’ ‘,’*')
– $****3,534.40
SELECT PaddedProductID =
dbo.fnLeftPadString (CONVERT(varchar, ProductID), ’0′, 6),
ProductName=Name,
ListPrice
FROM Production.Product
ORDER BY PaddedProductID
GO
/* Partial results
PaddedProductID ProductName ListPrice
000757 Road-450 Red, 48 1457.99
000758 Road-450 Red, 52 1457.99
000759 Road-650 Red, 58 782.99
000760 Road-650 Red, 60 782.99
000761 Road-650 Red, 62 782.99
*/
———-
– Generating tracking numbers
– SQL pad zeroes
WITH cteSequence(SeqNo)
AS (SELECT 1
UNION ALL
SELECT SeqNo + 1
FROM cteSequence
WHERE SeqNo < 1000000)
SELECT TOP 100 CAST((‘TRK’ + REPLICATE(’0′,
7 – LEN(CAST(SeqNo AS VARCHAR(6)))) +
CAST(SeqNo AS VARCHAR(6))) AS VARCHAR(10)) AS TrackingNo
FROM cteSequence
OPTION (MAXRECURSION 0)
GO
/* Partial results
TrackingNo
TRK0000001
TRK0000002
TRK0000003
TRK0000004
TRK0000005
TRK0000006
TRK0000007
*/
———-
– SQL server pad
– SQL str function
– SQL pad integer
– SQL left pad
SELECT TOP (4) StaffName=LastName+’, ‘+FirstName,
PaddedEmployeeID = REPLACE(STR(EmployeeID, 6, 0), ‘ ‘, ’0′)
FROM HumanResources.Employee e
INNER JOIN Person.Contact c
ON e.ContactID = c.ContactID
ORDER BY NEWID()
/* Results
StaffName PaddedEmployeeID
Dyck, Shelley 000214
Hines, Michael 000039
Ford, Jeffrey 000015
Caron, Rob 000168
*/
– SQL asterisk padding
– SQL pad with asterisk
– SQL right pad
SELECT TOP ( 2 * 2 )
AddressID
, City+REPLICATE(‘*’, 20-len(City)) AS City
, PostalCode
FROM AdventureWorks.Person.[Address]
WHERE LEN(City) <= 20
ORDER by NEWID()
GO
/*
AddressID City PostalCode
13465 Imperial Beach****** 91932
23217 Corvallis*********** 97330
18548 Milwaukie*********** 97222
24893 Goulburn************ 2580
*/
————
————
– SQL left pad any size string Alpha with any length string Beta
————
– SQL user-defined function – UDF – scalar-valued string function
– T-SQL varchar(max)
USE AdventureWorks2008;
GO
CREATE FUNCTION fnMaxPad
(@SourceString VARCHAR(MAX),
@PaddingString VARCHAR(MAX),
@OutputLength INT)
RETURNS VARCHAR(MAX)
AS
BEGIN
DECLARE @WorkString VARCHAR(MAX) =
ISNULL(REPLICATE(@PaddingString,@OutputLength – len(ISNULL(@SourceString,0))),
”) + @SourceString
RETURN RIGHT(@WorkString, @OutputLength)
END
GO
– Execute UDF
SELECT TOP ( 5 ) [SQL Padding Demo] =
dbo.fnMaxPad(CONVERT(VARCHAR,FLOOR(ListPrice)),’_/’,21)
FROM Production.Product
ORDER BY NEWID()
GO
/* Results
SQL Padding Demo
_/_/_/_/_/_/_/2443.00
/_/_/_/_/_/_/_/_/0.00
/_/_/_/_/_/_/_/147.00
/_/_/_/_/_/_/_/_/0.00
_/_/_/_/_/_/_/1003.00
*/
————
– SQL left pad unicode string Alpha with any length unicode string Beta
– MSSQL pad international
– SQL user-defined function – UDF – scalar-value function
– T-SQL nvarchar(max)
USE AdventureWorks2008;
GO
CREATE FUNCTION fnMaxPadInternational
(@SourceString NVARCHAR(MAX),
@PaddingString NVARCHAR(MAX),
@OutputLength INT)
RETURNS NVARCHAR(MAX)
AS
BEGIN
DECLARE @WorkString NVARCHAR(MAX) =
ISNULL(REPLICATE(@PaddingString,@OutputLength – len(ISNULL(@SourceString,0))),
”) + @SourceString
RETURN RIGHT(@WorkString, @OutputLength)
END
GO
– Execute UDF
SELECT TOP ( 5 ) [SQL Padding Demo] =
dbo.fnMaxPadInternational(LEFT(Description,6),’_/’,21)
FROM Production.ProductDescription
ORDER BY NEWID()
GO
/* Results
SQL Padding Demo
/_/_/_/_/_/_/_/ล้อที่
/_/_/_/_/_/_/_/Roue d
/_/_/_/_/_/_/_/شوكة ط
/_/_/_/_/_/_/_/Each f
/_/_/_/_/_/_/_/Jeu de
*/
————
Reference from sqlusa.com
How to configure SQL Server 2005 to allow remote connections?
To configure SQL Server 2005 to allow remote connections, complete all the following steps.
• Enable remote connections on the instance of SQL Server that you want to connect to from a remote computer.
• Turn on the SQL Server Browser service.
• Configure the firewall to allow network traffic that is related to SQL Server and to the SQL Server Browser service.
Enable remote connections for SQL Server 2005 Express
1. Click Start, point to Programs, point to Microsoft SQL Server 2005, point to Configuration Tools, and then click SQL Server Surface Area Configuration.
2. On the SQL Server 2005 Surface Area Configuration page, click Surface Area Configuration for Services and Connections.
3. On the Surface Area Configuration for Services and Connections page, expand Database Engine, click Remote Connections, click Local and remote connections, click the appropriate protocol to enable for your environment, and then click Apply.
Note Click OK when you receive the following message:
Changes to Connection Settings will not take effect until you restart the Database Engine service.
4. On the Surface Area Configuration for Services and Connections page, expand Database Engine, click Service, click Stop. wait until the MSSQLSERVER service stops, and then click Start to restart the MSSQLSERVER service.
Enable the SQL Server Browser service
1.Click Start, point to Programs, point to Microsoft SQL Server 2005, point to Configuration Tools, and then click SQL Server Surface Area Configuration.
2.On the SQL Server 2005 Surface Area Configuration page, click Surface Area Configuration for Services and Connections.
3.On the Surface Area Configuration for Services and Connections page, click SQL Server Browser, click Automatic for Startup type, and then click Apply.
Note When you click the Automatic option, the SQL Server Browser service starts automatically every time that you start Microsoft Windows.
4.Click Start, and then click OK.
Create exceptions in Windows Firewall
SQL Server 2005 uses an instance ID as part of the path when you install its program files. To create an exception for each instance of SQL Server, you must identify the correct instance ID. To obtain an instance ID, follow these steps:
1. Click Start, point to Programs, point to Microsoft SQL Server 2005, point to Configuration Tools, and then click SQL Server Configuration Manager.
2. In SQL Server Configuration Manager, click the SQL Server Browser service in the right pane, right-click the instance name in the main window, and then click Properties.
3. On the SQL Server Browser Properties page, click the Advanced tab, locate the instance ID in the property list, and then click OK.
To open Windows Firewall, click Start, click Run, type firewall.cpl, and then click OK.
Create an exception for SQL Server 2005 in Windows Firewall
To create an exception for SQL Server 2005 in Windows Firewall, follow these steps:
1. In Windows Firewall, click the Exceptions tab, and then click Add Program.
2. In the Add a Program window, click Browse.
3. Click the C:\Program Files\Microsoft SQL Server\MSSQL.1\MSSQL\Binn\sqlservr.exe executable program, click Open, and then click OK.
Note The path may be different depending on where SQL Server 2005 is installed. MSSQL.1 is a placeholder for the instance ID that you obtained in step 3 of the previous procedure.
4. Repeat steps 1 through 3 for each instance of SQL Server 2005 that needs an exception.
Create an exception for the SQL Server Browser service in Windows Firewall
To create an exception for the SQL Server Browser service in Windows Firewall, follow these steps:
1. In Windows Firewall, click the Exceptions tab, and then click Add Program.
2. In the Add a Program window, click Browse.
3. Click the C:\Program Files\Microsoft SQL Server\90\Shared\sqlbrowser.exe executable program, click Open, and then click OK.
–
Hope this helps everyone.
Differences between varchar and nvarchar in SQL Server
=>SQL Server 2000 and SQL Server 7, a row cannot exceed 8000 bytes in size. This means that a VARBINARY column can only store 8000 bytes (assuming it is the only column in a table), a VARCHAR column can store up to 8000 characters and an NVARCHAR column can store up to 4000 characters (2 bytes per unicode character). This limitation stems from the 8 KB internal page size SQL Server uses to save data to disk.
To store more data in a single column, you needed to use the TEXT, NTEXT, or IMAGE data types (BLOBs) which are stored in a collection of 8 KB data pages that are separate from the data pages that store the other data in the same table. These data pages are arranged in a B-tree structure. BLOBs are hard to work with and manipulate. They cannot be used as variables in a procedure or a function and they cannot be used inside string functions such as REPLACE, CHARINDEX or SUBSTRING. In most cases, you have to use READTEXT, WRITETEXT, and UPDATETEXT commands to manipulate BLOBs.
To solve this problem, Microsoft introduced the VARCHAR(MAX), NVARCHAR(MAX), and VARBINARY(MAX) data types in SQL Server 2005. These data types can hold the same amount of data BLOBs can hold (2 GB) and they are stored in the same type of data pages used for other data types. When data in a MAX data type exceeds 8 KB, an over-flow page is used. SQL Server 2005 automatically assigns an over-flow indicator to the page and knows how to manipulate data rows the same way it manipulates other data types. You can declare variables of MAX data types inside a stored procedure or function and even pass them as variables. You can also use them inside string functions.
The broad range of data types in SQL Server can sometimes throw people through a loop, especially when the data types seem to be highly interchangeable. Two in particular that constantly spark questions are VARCHAR and NVARCHAR: what’s the difference between the two, and how important is the difference?
VARCHAR is an abbreviation for variable-length character string. It’s a string of text characters that can be as large as the page size for the database table holding the column in question. The size for a table page is 8,196 bytes, and no one row in a table can be more than 8,060 characters. This in turn limits the maximum size of a VARCHAR to 8,000 bytes.
The “N” in NVARCHAR means uNicode. Essentially, NVARCHAR is nothing more than a VARCHAR that supports two-byte characters. The most common use for this sort of thing is to store character data that is a mixture of English and non-English symbols — in my case, English and Japanese.
The key difference between the two data types is how they’re stored. VARCHAR is stored as regular 8-bit data. But NVARCHAR strings are stored in the database as UTF-16 — 16 bits or two bytes per character, all the time — and converted to whatever codepage is being used by the database connection on output (typically UTF-8). That said, NVARCHAR strings have the same length restrictions as their VARCHAR cousins — 8,000 bytes. However, since NVARCHARs use two bytes for each character, that means a given NVARCHAR can only hold 4,000 characters (not bytes) maximum. So, the amount of storage needed for NVARCHAR entities is going to be twice whatever you’d allocate for a plain old VARCHAR.
Because of this, some people may not want to use NVARCHAR universally, and may want to fall back on VARCHAR — which takes up less space per row — whenever possible.
Time Delay While Running T-SQL Query – Sleep Facility in SQL Server
Today, When I was created one store procedure, I fetched one problem. I have created on store procedure which will
generate 25 digits Primary key based on date and time.
I have to generate the primary key for 100k records to insert into another table.
I was using my Store procedure to generate the ID, but it gives me error which is very familiar for us.
Violation of PRIMARY KEY constraint
Now i have searching for function or way to wait for seconds or mili seconds in sql which is vary familiar in our programming language Sleep method to wait for some time before completion of code.
Today I will explain one very small but interesting feature of SQL Server. This is not much known feature of SQL Server. In SQL Server sometime, there are requirement like I described above when T-SQL script has to wait for some time before executing next statement. It is quite common that developers depends on application to take over this delay issue. However, SQL Server itself has very strong time management function of WAITFOR. Let us see two usage of WAITFOR clause.
Official explanation of WAITFOR clause from Book Online is “Blocks the execution of a batch, stored procedure, or transaction until a specified time or time interval is reached, or a specified statement modifies or returns at least one row.”
Please run the following query into your sql server query analyzer.
SELECT GETDATE()
WAITFOR DELAY ’00:00:00:010′
– wait for 10 mill seconds to run the below code
SELECT GETDATE()
–
Happy programming
Update data in one table with data from another table
How to update more than one column in a table with values
from columns in another table and explains how to do it in the three RDBMS that we support.
Table Structures and values:
TableA has four columns: a, b, c, d (a is the primary key column)
TableB has five columns: a1, b1, c1, d1, e1 (a1 and b1 together constitute the primary key for this table)
The foreign key relationship between the two tables is based on A.a = B.a1
The data in these 2 tables is as follows:
I. TableA
a b c d
1 x y z
2 a b c
3 t x z
II. TableB
a1 b1 c1 d1 e1
1 x1 y1 z1 40
2 a1 b1 c1 50
The requirement is to write a SQL to update columns b, c and d in TableA from the columns b1, c1 and d1 from TableB where-ever the join condition satisfies and e1 > 40 in TABLEB.
SQL Server:
UPDATE TABLEA
SET b = TABLEB.b1,
c = TABLEB.c1,
d = TABLEB.d1
FROM TABLEA, TABLEB
WHERE TABLEA.a = TABLEB.a1
AND TABLEB.e1 > 40
GO
Note: This is an extension in SQL Server i.e. the FROM clause – it does make it simple to understand and is a nice feature.
Results after the update:
a b c d
————————————
1 x y z
2 a1 b1 c1
3 t x z
NOTE:
It is very important to make sure that your where clause for the update statement is correct since
that is what identifies the records that the update statement is going to qualify and do the update upon.
If it is incorrect, then you can get wrong results. The reason I am mentioning this is
because I have seen people write wrong where clauses and then wondering what went wrong
because they specified the correct condition in the SET clause.
In the above example,
if the Where condition was omitted, the other record’s columns would be updated to NULL value
and this will be the final result set:
a b c d
————————————
1 Null Null Null
2 a1 b1 c1
3 Null Null Null
–
happy programming
Date and time types in SQL Server
Prior to SQL Server 2008, there are two types in SQL Server to handle date and time. Since I will be referring to these types a lot, I introduce an abbreviation for each type in below two tables (the “sn” column):
| Name | sn | Minimum value | Maximum value | Accuracy | Storage |
| smalldatetime | sdt | 1900-01-01 00:00:00 | 2079-06-06 23:59:00 | minute | 4 bytes |
| datetime | dt | 1753-01-01 00:00:00.000 | 9999-12-31 23:59:59.997 | 3.33 ms | 8 bytes |
Note that there is no type to store only date or only time. Above types, have both a date and a time portion.
If you only specify a date portion, then SQL Server will store 00:00:00.000 in the time portion.
And if you only specify a time portion, SQL Server will store 1900-01-01 in the date portion.
Above is important. Read it again.
SELECT CAST ('20041223' AS datetime)
-----------------------
2004-12-23 00:00:00.000
SELECT CAST ('14:23:58' AS datetime)
-----------------------
1900-01-01 14:23:58.000
As of SQL Server 2008, we have several new types related to date and time:
| Name | sn | Minimum value | Maximum value | Accuracy | Storage |
| datetime2 | dt2 | 0001-01-01 00:00:00.0000000 | 9999-12-31 23:59:59.9999999 | 100ns | 6-8 bytes |
| date | d | 0001-01-01 | 9999-12-31 | day | 3 bytes |
| time | t | 00:00:00.0000000 | 23:59:59.9999999 | 100ns | 3-5 bytes |
| datetimeoffset | dto | 0001-01-01 00:00:00.0000000 | 9999-12-31 23:59:59.9999999 | 100ns | 8-10 bytes |
- As you can see, we have finally a date-only and a time-only type.
- Datetime2 is a “better datetime” for various reasons, and it does not cost any more storage than datetime – potentially less!
- For the new types, which include a time portion, you can specify a “fractional seconds precision” part, which specifies how many digits you have to the right of the comma after the second. So, for instance time (3) can store a value like 14:23:12.567, where if you input 14:23:12.5677 it will be rounded to 14:23:12.568.
- The new datetimeoffset includes a time zone offset part.
Date and time formats
A common misconception is that SQL Server stores these datatypes in some particular readable format. That is not the case. SQL Server stores these values in an internal format (for instance two integers for datetime and smalldatetime). However, when you use T-SQL to specify a value (in an INSERT statement, for instance) you express it as a string. And there are rules for how different datetime string formats are interpreted by SQL Server. But note that SQL Server does not remember the format in any way.
Date and time formats for input
There are many formats available for us to specify a date/time/datetime value. Some are “better” than others are and as you read this article, I hope you will understand what I mean by “better”. Interestingly enough, all formats are available for all types. So even a time-only format is allowed for a date-only type etc.
(I am ignoring the time zone offset part, which is only used for the datetimeoffset type – you can read more about this in Books Online.)
| Name | sn | Format | SET DATEFORMAT dependent | SET LANGUAGE dependent | language neutral |
| Unseparated | u | ’19980223 14:23:05′ | none | none | all |
| Separated | s | ’02/23/1998 14:23:05′ | all | all | no |
| ANSI SQL | ansisql | ’1998-12-23 14:23:05′ | sdt, dt | sdt, dt | not for sdt and dt |
| Alphabetic | a | ’23 February 1998 14:23:05′ | none | all (month name) | no |
| ODBC datetime | odt | {ts ’1998-02-23 14:23:05′} | none | none | all |
| ODBC date | od | {d ’1998-02-23′} | none | none | all |
| ODBC time | ot | {t ’14:23:05′} | none | none | all |
| ISO 8601 | iso | ’1998-02-23T14:23:05′ | none | none | all |
| Time | t | ’14:23:05′ ’2:23:05 PM’ |
none | none | all |
- Note that ANSI SQL is really only a special case of the separated (aka “numeric”) format, which allow for separators dash (-), slash (/) and dot (.). But since this is the only format defined in the ANSI SQL standard, I think it is worth mentioning this as a special case.
- Most formats allow for dropping the date and/or the time portion, and in some cases, it can look a bit … strange. It might seem stupid to specify for instance ’2008-08-25′ for a time type, but doing that result in same as specifying nothing in the datetime string, ”. Consider below:
SELECTCAST(''AStime)SELECTCAST('2008-08-25'AStime)above two gives, us the same result (time 00:00:00).
- The ODBC formats are different in the sense that they have a marker (literal_type, t, d or ts), you need to define correctly depending on whether you specify both date and time, date only or time only.
- The ISO 8601 format requires both a date and a time portion.
- SET DATEFORMAT inherits its setting from SET LANGUAGE (but an explicit SET DATEFORMAT will override later SET LANGUAGE). The language defaults to each login’s language. Default language for a login is specified using sp_configure.
- The rules regarding the format for the date part and the new types can be confusing. Microsoft wanted to make the new date related types (date, datetime2 and datetimeoffset) less dependent on these settings and more ANSI SQL compliant. End result is that these new types are language neutral for a separated datetime literal as long as the year comes first. SQL Server need to determine that this is the year part, so it requires 4 numbers year (yyyy, not yy). If that is the case, then the string will be interpreted as year first, then month and finally day – regardless of DATEFORMAT or language setting. But if the month part comes first, then DATEFORMAT and language setting will be “honored”:
SET LANGUAGE British --uses dmy
GO
SELECT CAST('02-23-1998 14:23:05' AS date) --Error
GO
SELECT CAST('2/23/1998 14:23:05' AS date) --Error
GO
SELECT CAST('1998-02-23 14:23:05' AS date) --Ok
GO
SELECT CAST('1998.02.23 14:23:05' AS date) --Ok
GO
SELECT CAST('1998/02/23 14:23:05' AS date) --Ok
GO
The first two fails because the year doesn’t come first (and there are not 23 months in 1998). The last three doesn’t fail because the year comes first (and we are using one of the new style date related types).
Crystal clear, huh? :-)
The available formats are documented in Books Online, so I won’t go into details about each format. Here’s a link to the online version of Books Online, see each subsection for the different formats.
Note that the ODBC time only format will give the current date, not 1900-01-01 as the other time-only formats.
Some conclusions:
- The Alphabetic format is especially bad since this is SET LANGUAGE dependent for all types.
- The smalldatetime and datetime types are unfortunate since they are dependent on not only SET LANGUAGE but also SET DATEFORMAT (including the login’s language setting).
- You might think that it doesn’t matter if a format/type combination is SET LANGUAGE dependent or not since “I never execute that SET LANGUAGE command anyhow”. But note very carefully that the default for DATEFORMAT is drawn from the login specification (CREATE LOGIN etc.). Imagine for instance an app developed in the US with login having default language (us_english) using m/d/y format and date time. Somebody in, say, Germany installs it and bang! The app does not work anymore. Do I have your attention now? :-)
- The types introduced in 2008 are friendlier since they are not SET DATEFORMAT dependent if you for a separated format specify the year first. For the separated formats (including ANSI SQL), the new types always interprets month before date.
Recommendations for input
As you probably realize, you don’t want to use a combination of format and type, which isn’t language neutral unless you make sure that you have the correct DATEFORMAT and LANGUAGE settings in your applications. Be aware that setting these options inside a stored procedure can cause a recompile of the procedure at execution time!
My recommendation is to use a language neutral format. I typically use the unseparated format, mostly out of old habit. The ISO 8601 format has the advantage of being defined in an international standard.
SQL Server 2008 has just been released at the time of writing this, but I will probably move towards date, time, datetime2 and possibly datetimeoffset over time. Over time, I might be using the ANSI SQL format (being ANSI SQL compliant) with the new types, but i’d rather that ANSI SQL supports the ISO 8601 format. I will play it safe and use unseparated or ISO 8601 for a number of years to come – even when working with the new types.
Warnings and common misconceptions
Let me say this again: you don’t want to use a combination of format and type, which isn’t language neutral unless you make sure that you have the correct DATEFORMAT and LANGUAGE settings in your applications.
The Numeric format can use dash (-), dot (.) or slash (/) as separator. The rules for how SQL Server parses the string doesn’t change depending on the separator. A common misconception is that the ANSI SQL format (sometime a bit incorrectly referred to as the “ISO format”), 1998-02-23, is language neutral for smalldatetime and datetime. It isn’t. It is a numeric format and hence it is dependent on the SET DATEFORMAT and SET LANGUAGE setting:
SET LANGUAGE us_english
SELECT CAST('2003-02-28' AS datetime)
-----------------------
2003-02-28 00:00:00.000
SET LANGUAGE british
SELECT CAST('2003-02-28' AS datetime)
Server: Msg 242, Level 16, State 3, Line 4
The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value.
Please read the error message closely. It says exactly what the problem is. You specify the datetime value as a string, and because the string isn’t formed according to the format you are using and the DATEFORMAT setting, SQL Server cannot convert the string to a datetime value.
Output of datetime values
When a datetime value leaves SQL Server is has no readable format. It is the client application that formats the value so it is human-readable. Some applications/developer environments will respect the regional settings of the client machine and format the value accordingly. But this is out of SQL Server’s control. You can return the data from SQL Server using a specific format, but that requires you to convert it to a string, and the value will not be of the datetime type anymore. If you want to do this, use the CONVERT function, which has a useful 3:rd parameter that defines the format when you convert from datetime to a string. A few examples:
SELECT CONVERT(char(8), CURRENT_TIMESTAMP, 112)
--------
20040312
SELECT CONVERT(char(19), CURRENT_TIMESTAMP, 120)
-------------------
2004-03-12 18:08:43
SELECT CONVERT(char(10), CURRENT_TIMESTAMP, 103)
----------
12/03/2004
Searching for datetime values
The problem with datetime searches often comes from the fact that if you use smalldatetime, datetime, datetime2 or datetimeoffset then there is both a date and a time portion. Let’s create table that we will use in a couple of examples:
CREATE TABLE #dts(c1 char(1), dt datetime)
INSERT INTO #dts (c1, dt) VALUES('a', '20040305 09:12:59')
INSERT INTO #dts (c1, dt) VALUES('b', '20040305 16:03:12')
INSERT INTO #dts (c1, dt) VALUES('c', '20040306 00:00:00')
INSERT INTO #dts (c1, dt) VALUES('d', '20040306 02:41:32')
INSERT INTO #dts (c1, dt) VALUES('e', '20040315 11:45:17')
INSERT INTO #dts (c1, dt) VALUES('f', '20040412 09:12:59')
INSERT INTO #dts (c1, dt) VALUES('g', '20040523 11:43:25')
Say that we want to find all rows from 2004-03-15. A common mistake is to search like this:
SELECT c1, dt FROM #dts WHERE dt = '20040305'
No rows returned. Why? What happened? We have two different types in the WHERE clause, a datetime type (the column side) and a string (the right side). SQL Server will convert one to the other according to the documented “Data Type Precedence” in Books Online. Datetime has higher precedence than a string so the string will first be converted to a datetime type. As we didn’t specify a time portion, the string will be converted to the datetime value 2004-03-05 00:00:00. There are no rows with that datetime value.
OK, another alternative. We use the CONVERT function on the column side and convert it to a string so it matches the string format on the right side:
SELECT c1, dt FROM #dts WHERE CONVERT(char(8), dt, 112) = '20040305'
That returned the expected rows, but there’s another problem. Since we do a calculation on the column side (using the CONVERT function), SQL Server cannot use an index to support this search criteria. This can be disastrous for performance! So let’s try BETWEEN:
SELECT c1, dt FROM #dts WHERE dt BETWEEN '20040305' AND '20040306'
Because BETWEEN is inclusive, we also returned the row from 2004-03-06 00:00:00. Let’s try to handle that:
SELECT c1, dt FROM #dts WHERE dt BETWEEN '20040305' AND '20040305 23:59:59.999'
What? We still got the row from 2004-03-06 00:00:00 back. Why? We need to look at the type definitions again. The resolution for the datetime type is 3.33 ms. That means that 2004-03-05 23:59:59.999 will be rounded up to 2004-03-06 00:00:00.000. Not what we expected. To get around that rounding problem, we try:
SELECT c1, dt FROM #dts WHERE dt BETWEEN '20040305' AND '20040305 23:59:59.997'
Above return the expected rows, but I would not call it intuitive and easy to read. Also, if the type in the table is smalldatetime instead of datetime, the time portion will again be rounded up, hence not producing the expected rows. So you find yourself having two ways of doing this dependent on whether you have datetime or smalldatetime. If the type is smalldatetime, you would use:
SELECT c1, dt FROM #dts WHERE dt BETWEEN '20040305' AND '20040305 23:59:00'
Having two different ways of doing this depending on the datatype is not something I recommend. And, who knows if Microsoft in the future will add types with higher precision for the time portion (which they did in SQL Server 2008)? Again you would have to adjust the time portion in the WHERE clause. Below you find my recommendation:
SELECT c1, dt FROM #dts WHERE dt >= '20040305' AND dt < '20040306'
We get the expected rows back and it is easy to understand what the criteria means. And SQL Server can use an index on the dt column. This is also easy to expand for searches on greater ranges. Say we want to return all rows for March 2004:
SELECT c1, dt FROM #dts WHERE dt >= '20040301' AND dt < '20040401'
Same logic. Here’s another way to search for all rows from a specific month:
SELECT c1, dt FROM #dts WHERE DATEPART(year, dt) = 2004 AND DATENAME(month, dt) = 'March'
Above returns the expected rows, but there are two problems. Since there is a calculation on the datetime column, SQL Server cannot use an index on the dt column to support the query. And, the DATENAME function is dependent on SET LANGUAGE.
Getting rid of the time portion
It is very common that you only want to work with date, and you want to get rid of the time portion. As you should know by now it is impossible if you are a using smalldatetime, datetime, datetime2 or datetimeoffset type. If you are using date, then no problem – this is what date is for, after all! But if you insist for some reason to use smalldatetime, datetime, datetime2 or datetimeoffset then perhaps setting the time portion to 00:00:00 is fine for you? Here’s my suggestion for an expression that returns a string that can be (implicitly) converted to a datetime value, regardless of SET LANGUAGE or DATEFORMAT:
CONVERT(char(8), CURRENT_TIMESTAMP, 112)
As you see, I use CONVERT with conversion code 112, which return the date in unseparated format, as a string. And you already know that the unseparated format is interpreted regardless of datetime or language settings when converted to datetime. Let us wrap above in a CAST to convert it to datetime:
SELECT CAST(CONVERT(char(8), CURRENT_TIMESTAMP, 112) AS datetime)
In case you truly only want to return the date and no time portion to the client application, then you have to return a string instead (or as of 2008, the date type). Again, read about the different conversion codes for the CONVERT function and you will probably find a format which suits you.
Hugo Kornelis had some feedback on this topic and suggests another technique for setting the time portion to 00:00:00. The idea is to decide on a base date (any date within SQL Server’s datetime range will do), specify it so that time portion is 00:00:00. You first take the difference between today and this base date, in days. Then you add this number of days to the base date. Algorithm: [today]-[refdate]+[refdate], or expressed with TSQL (using 20040101 as base date):
SELECT DATEADD(day, DATEDIFF(day, '20040101', CURRENT_TIMESTAMP), '20040101')
An argument for above is that is is faster than doing string manipulations. My opinion has been that the difference is so small (a few microseconds according to tests I did about year 2000) so that this would probably not even be measurable. However SQL Server MVP Dan Guzman emailed me with some to me surprising information. Here’s a quote from the email:
“I’ve found that the DATEADD technique significantly outperforms the string method when the expression is applied to a column in large queries. For example, I often use the DATEADD method to group by date when the datetime column includes a time component. I haven’t tested the performance recently but I recall it was minutes in some cases.”
Dan is someone I trust very much, so I guess I have some re-learning to do (start using the DATEADD method instead of the string method). Dan also followed up with a script file showing this. Here it is (with some minor formatting modifications made by me). My tests show consistent results on 2005 and 2008 where for 10,000,000 rows the DATEADD version took about 6 seconds and the string version took about 13 seconds. Dan reported even greater difference on 2000.
2009-04-03, I received an email from Håkan Borneland. He mentioned that is is common, for instance in the MSDN forums, to use first alternative below, instead of second alternative (which I had originally in my performance test script):
SELECT DATEADD(DAY, 0, DATEDIFF(DAY, 0, CURRENT_TIMESTAMP))
SELECT DATEADD(DAY, 0, DATEDIFF(DAY, '', CURRENT_TIMESTAMP))
Note that both these differs from the DATEDIFF version discussed slightly higher above. So now we have 4 different ways to accomplish this. “My” original string manipulation method and three DATEDIFF alternatives:
SELECT CAST(CONVERT(CHAR(8), CURRENT_TIMESTAMP, 112) AS datetime) --1
SELECT DATEADD(DAY, 0, DATEDIFF(DAY, '', CURRENT_TIMESTAMP)) --2
SELECT DATEADD(DAY, DATEDIFF(DAY, '20040101', CURRENT_TIMESTAMP), '20040101') --3
SELECT DATEADD(DAY, 0, DATEDIFF(DAY, 0, CURRENT_TIMESTAMP)) --4
If you feel that you do operations so that performance can be a major concern, then I suggest you test. Here is an updated performance test script, with all four versions. Alternative 1 is slowest and the three DATEDIFF alternatives (2-4) are pretty close with alternative 4 as the winner. I also suggest you consider readability, which can be a matter of oppinion.
The DATEADD alternative also has the advantage of flexibility. Instead of re-typing the suggestions from Hugo, I’ve just copied the original text from Hugo in the email he sent to me:
“The version that uses string conversion can only be used to strip the time from the date. The dateadd/datediff version can easily be varied to get the start of the current month, quarter or year. SELECT DATEADD(month, DATEDIFF(month, ’20000101′, CURRENT_TIMESTAMP), ’20000101′) Or to discard only minutes and seconds, or only seconds SELECT DATEADD(hour, DATEDIFF(hour, ’20000101′, CURRENT_TIMESTAMP), ’20000101′) (Note – when dealing with minutes, seconds or milliseconds, the DATEDIFF function CAN overflow the integer range – the date constant might have to be adapted to the expected set of datetime values). Further variations are also possible: How to get the last day of the previous month? And the last day of the current month?
SELECT DATEADD(month, DATEDIFF(month, '20000101', CURRENT_TIMESTAMP), '19991231')
SELECT DATEADD(month, DATEDIFF(month, '20000101', CURRENT_TIMESTAMP), '20000131')
How to get tomorrow’s date (without time)?
SELECT DATEADD(day, DATEDIFF(day, '20000101', CURRENT_TIMESTAMP), '20000102')
How to round the datetime to the nearest hour, or to the nearest day?
SELECT DATEADD(hour, DATEDIFF(hour, '20000101', DATEADD(minute, 30, CURRENT_TIMESTAMP)), '20000101')
SELECT DATEADD(day, DATEDIFF(day, '20000101', DATEADD(hour, 12, CURRENT_TIMESTAMP)), '20000101')
How to get last Friday’s date, without using a calendar table and regardless of the current DATEFIRST setting?
SELECT DATEADD(day, (DATEDIFF (day, '20000107', CURRENT_TIMESTAMP) / 7) * 7, '20000107')
or
SELECT DATEADD(day, (DATEDIFF (day, '20000108', CURRENT_TIMESTAMP) / 7) * 7, '20000107')
The first will return the current day if run on friday, the latter will return the previous friday.
Once you understand the general principle, it isn’t hard to come up with new variations, that might be useful in specific circumstances.
“Tip: Always set the time to the same value
If you aren’t interested in the time portion and you can’t use the date type, you can set the time portion to a standard value for all rows. I recommend 00:00:00.000. Say you want to set the value to the current date when the INSERT is performed. For that you can use a DEFAULT constraint:
CREATE TABLE #dts(id INT IDENTITY, d_date DATETIME DEFAULT CONVERT(char(8), CURRENT_TIMESTAMP, 112))
INSERT #dts DEFAULT VALUES
SELECT * FROM #dts
I’m using the code 112 in the CONVERT() function above, which returns a string with the date only, in the unseparated format. However, we have not protected us from if anyone now explicitly sets the value and set the time portion to something other than 00:00:00:000. We can do that with a constraint:
ALTER TABLE #dts ADD CONSTRAINT dts_chk_d_date CHECK(CONVERT(char(12), d_date, 114) = '00:00:00:000')
What advantage does above give us? If we now want to search for all rows from a certain date, we can write the WHERE clause like:
WHERE dt = '20040305'
Above might be considered easier to read and understand. Also, say you want to join between two table based on the day only, you can now do this directly. If you have a time portion that varies, you would have to use some CONVERT in the JOIN operation which again can be disastrous for performance.
Above technique can also be applied if you are only interested in the time portion, in that case I recommend that you always set the date portion to 1900-01-01.
Now, isn’t it great that we as of 2008 have separate data and time types?
Other tips, from SQL Server MVP Steve Kass
The super-careful can specify all dates in queries as smalldatetime, using cast or convert. But note that this may have unexpected behavior in SQL Server 7.0 against a (not small-) datetime column.
Without a very good reason and comments everywhere, store dates only as datetime or smalldatetime, and not as strings. If dates must be stored as strings (there are some good reasons to, but they are few), use a language neutral format and a 24-hour clock if time is also stored, so that the strings work everywhere and also sort the way the dates sort. For example, you use “dt < ’20030101′” in the WHERE clause and the query doesn’t return expected rows because dt is stored as a string in yyyy-mm-dd format.
The base date in Enterprise Manager (and some other Microsoft tools and applications) is 1899-12-30. EM should never be used for data entry, and rarely if ever for viewing data. If you use EM to specify time-only data, EM will store the date 1899-12-30. If you really want to use EM, specify the date 1900-01-01 explicitly. Note also that EM will only show the time portion if the date is 1899-12-30, not what you expect if you use 1900-01-01 as a standard value for date.
Why is 1753 the earliest date for datetime?
Good question. It is for historical reasons. In what we sometimes refer to as the western world, we have had two calendars in modern time: the Julian and the Gregorian calendars. These calendars were a number of days apart (depending on which century you look at), so when a culture that used the Julian calendar moved to the Gregorian calendar, they dropped from 10 to 13 days. Great Britain made this shift in 1752 (1752-09-02 were followed by 1752-09-14). An educated guess why Sybase selected 1753 as earliest date is that if you were to store an earlier date than 1753, you would also have to know which country and also handle this 10-13 day jump. So they decided to not allow dates earlier than 1753. Note, however that other countries did the shift later than 1752. Turkey, for instance, did it as late as 1927.
Being Swedish, I find it a bit amusing that Sweden had the weirdest implementation. They decided to skip the leap day over a period of 40 years (from 1700 to 1740), and Sweden would be in sync with the Gregorian calendar after 1740 (but meanwhile not in sync with anyone). However, in 1704 and 1708 the leap day was not skipped for some reason, so in 1712 which was a leap year, they inserted yet an extra day (imagine being born in Feb 30!) and then did the shift over a day like everyone else, in 1753.
Ten Common SQL Programming Mistakes
Without further ado, here is the list:
- NULLs and the NOT IN predicate
- Functions on indexed columns in predicates
- Incorrect subquery column
- Data type mismatch in predicates
- Predicate evaluation order
- Outer joins and placement of predicates
- Subqueries that return more than one value
- Use of SELECT *
- Scalar user-defined functions
- Overuse of cursors
The examples are presented using SQL Server’s Transact-SQL dialect, but most of the concepts are valid in any SQL implementation.
Read full article here
–
Happy Programming
Use Output clause in Delete Statement in sqlserver 2005
Here i give simple example of delete statement with output clause.
if you want track the deleted row information at that time generally
we preffered trigger right?
here we inserte the deleted row in the other history table. we create
the two talbe one is data table and other for history purpose.
1) Create Table (Name:Table_1)
GO
CREATE TABLE [dbo].[Table_1]
( [id] [int] IDENTITY(1,1) NOT NULL,
[varchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
CONSTRAINT [PK_Table_1] PRIMARY KEY CLUSTERED ( [id] ASC )WITH (IGNORE_DUP_KEY = OFF) ON [PRIMARY] ) ON [PRIMARY]
2) Create Table For Save Deleted Record in other table (DeletedTblInfo)
GO
CREATE TABLE [dbo].[DeletedTblInfo]
( [DeletedTableInfoId] [int] IDENTITY(1,1) NOT NULL,
[DeletedTableId] [int] NULL,
[DeletedRowId] [int] NULL,
[DeletedDateTime] [datetime] NULL,
CONSTRAINT [PK_DeletedTblInfo] PRIMARY KEY CLUSTERED ( [DeletedTableInfoId] ASC )WITH (IGNORE_DUP_KEY = OFF) ON [PRIMARY] ) ON [PRIMARY]
3) insert data into data table
go
INSERT INTO Table_1
(code)
VALUES
(‘test1′)
go
INSERT INTO Table_1
(code)
VALUES
(‘test2′)
go
INSERT INTO Table_1
(code)
VALUES
(‘test3′)
go
INSERT INTO Table_1
(code)
VALUES
(‘test4′)
4) now delete from table 1 where id =4
–here the record save in the DeletedTblInfo
–DeletedTableId : the table id where data is deleted or the table name if you want then.
–DeletedRowId : deleted RowId
–DeletedDateTime : deleted DateTime
DELETE FROM Table_1
OUTPUT 1,DELETED.ID,getdate()
INTO DeletedTblInfo WHERE (Id = 4);
–now see the result in the history table
DeletedTableInfoId DeletedTableId DeletedRowId DeletedDateTime 1 1 4 5/7/2008 12:53:52 PM
EXISTS or COUNT(*) Which Do You Use To Check How Many Rows There Are?
Do you use this
IF (SELECT COUNT(*) FROM SomeTable
WHERE SomeColumn = SomeValue ) > 0
Or do you use this
IF EXISTS (SELECT * FROM SomeTable WHERE SomeColumn = SomeValue )
If you answered COUNT(*) then maybe you should take a look these two articles
Andrew Kelly has a nice post on SQLBlog
http://sqlblog.com/blogs/andrew_kelly/archive/2007/12/15/exists-vs-count-the-battle-never-ends.aspx
Matija Lah has a good post on his snaps & snippets blog
http://milambda.blogspot.com/2006/10/exists-or-not-exists-that-is-question.html
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